Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analysis of Variance - Chapter 10 Test Prep - Review Exercises - Page 1000: 9

Answer

$${y^2} = 16x$$

Work Step by Step

$$\eqalign{ & {\text{focus}}\left( {4,0} \right) \cr & {\text{The focus is }}\left( {p,0} \right),{\text{ then the equation is of the form }} \cr & {y^2} = 4px \cr & {\text{with }}p = 4 \cr & {y^2} = 4\left( 4 \right)x \cr & {y^2} = 16x \cr} $$
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