Answer
$$\eqalign{
& \,\,\,{\text{Vertex }}\left( {h,k} \right) \to {\text{Vertex }}\left( { - 1, - 7} \right) \cr
& \,\,\,\,\,\,\,{\text{Horizontal axis of symmetry}} \cr
& \,\,\,\,\,\,\,{\text{Domain: }}\left( { - \infty ,h} \right]:\left( { - \infty , - 7} \right] \cr
& \,\,\,\,\,\,\,{\text{Range:}}\left( { - \infty ,\infty } \right) \cr} $$
Work Step by Step
$$\eqalign{
& x = - {\left( {y + 1} \right)^2} - 7 \cr
& x + 7 = - {\left( {y + 1} \right)^2} \cr
& - \left( {x + 7} \right) = {\left( {y + 1} \right)^2} \cr
& {\left( {y + 1} \right)^2} = - \left( {x - \left( { - 7} \right)} \right) \cr
& {\text{The equation is written in the form }}{\left( {y - k} \right)^2} = 4p\left( {x - h} \right) \cr
& {\left( {y + 1} \right)^2} = - \left( {x - \left( { - 7} \right)} \right) \to k = - 1,\,\,\,h = - 7 \cr
& \cr
& {\text{With: }} \cr
& \,\,\,\,\,\,{\text{Vertex }}\left( {h,k} \right) \to {\text{Vertex }}\left( { - 1, - 7} \right) \cr
& \,\,\,\,\,\,\,{\text{Horizontal axis of symmetry}} \cr
& \,\,\,\,\,\,\,{\text{Domain: }}\left( { - \infty ,h} \right]:\left( { - \infty , - 7} \right] \cr
& \,\,\,\,\,\,\,{\text{Range:}}\left( { - \infty ,\infty } \right) \cr} $$
