Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analysis of Variance - Chapter 10 Test Prep - Review Exercises - Page 1000: 15

Answer

$${\text{hyperbola}}$$

Work Step by Step

$$\eqalign{ & 3{y^2} - 5{x^2} = 30 \cr & {\text{Divide both sides by 30}} \cr & \frac{{3{y^2}}}{{30}} - \frac{{5{x^2}}}{{30}} = \frac{{30}}{{30}} \cr & \frac{{{y^2}}}{{10}} - \frac{{{x^2}}}{6} = 1 \cr & {\text{The equation is written in the form }}\frac{{{y^2}}}{{{a^2}}} - \frac{{{x^2}}}{{{b^2}}} = 1\, \cr & {\text{Therefore,}} \cr & {\text{The graph of the equation is a hyperbola}} \cr} $$
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