Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 130: 25

Answer

The rug is $9$ft by $12$ft

Work Step by Step

The room is $12$ft by $15$ft, and the rug has an even gap $x$, all around the walls resulting in a rug with and area of $108$ft$^2$ Since there is a gap on each side of the rug, Rug width = width of the room minus 2x = $12-2x$ Rug length = length of the room minus 2x = $15-2x$ We know that the formula for area of a rectangle is $(width)(length)=area$ so: $(12-2x)(15-2x)=108$ $180-24x-30x+4x^2=108$ $4x^2 -54x+180=108$ If we rewrite in standard quadratic equation form $ax^2 + bx +c=0$, $4x^2-54x+72=0$ where $a=4$, $b=-54$, and $c=72$, we can solve by applying the quadratic formula: $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ $x=\dfrac{(-)(-54)\pm\sqrt{(-54)^2-4(4)(72)}}{2(4)}$ $x=\dfrac{54\pm\sqrt{2916-1152}}{8}$ $x=\dfrac{54\pm\sqrt{1764}}{8}$ $x=\dfrac{54\pm42}{8}$ $x=\dfrac{54+42}{8}$ or $x=\dfrac{54-42}{8}$ $x=\dfrac{96}{8}$ or $x=\dfrac{12}{8}$ $x=12$ or $x=1.5$ Now we test our $x$ values in our formula, $(12-2x)(15-2x)=108$ If $x=12$: $[12-2(12)]\times[15-2(12)]=108$ $(12-24)(15-24)=108$ $(-12)(-9)=108$ which is mathematically correct, but the rug CANNOT have a negative length or width If $x=1.5$: $[12-2(1.5)]\times[15-2(1.5)]=108$ $(12-3)(15-3)=108$ $(9)(12)=108$ So the dimensions of the rug are $9$ft by $12$ft
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