Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 130: 22

Answer

7 and 12

Work Step by Step

Let x be the side of the smaller square. Then according to question. (x+5) is the side of the bigger square. Area of the square is given by $(side)^{2}$. Thus $(x+5)^{2}-x^{2}=95$ Simplify the expression $x^{2}+10x+25-x^{2}=95$ Combine the like terms and solve. $10x=70$ $x=7$ Thus side of smaller square = 7in And side of bigger square = 7+5 = 12in
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