Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 129: 9

$7,8$

Lets call the first integer x, and the second x + 1 $x(x+1) = 56$ $x^2 + x = 56$ $x^2 + x -56 = 0$ $(x-7)(x+8) = 0$ $x = -8, 7$ The correct solution is 7, because -8 is not an integer. Therefore the numbers are $7,8$.