Answer
$$7,9$$
Work Step by Step
The difference of the squares of two consecutive odd integers equals 32, which can be represented as
$(x+2)^2-(x)^2=32$
$x^2+4x+4-x^2=32$
$4x+4=32$
$4x=28$
$x=7$
Substitute $7$ for $x$ into the original equation and check
$(7+2)^2-7^2=32$
$9^2-7^2=32$
$81-49=32$
$7,9$