Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises: 12

Answer

$14,16$

Work Step by Step

Call the first integer x, and the second x + 2 $x(x+2) = 224$ $x^2 + 2x = 224$ $x^2 + 2x -224= 0$ $(x-14)(x+16) = 0$ $x = -16, 14$ The correct solution is 14, because -16 is not an integer. Therefore the numbers are $14,16$.
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