## Precalculus (6th Edition)

$14,16$
Call the first integer x, and the second x + 2 $x(x+2) = 224$ $x^2 + 2x = 224$ $x^2 + 2x -224= 0$ $(x-14)(x+16) = 0$ $x = -16, 14$ The correct solution is 14, because -16 is not an integer. Therefore the numbers are $14,16$.