#### Answer

The equation has two irrational solutions.

#### Work Step by Step

$2x^{2}+4x+1=0$
The discriminant is given by $b^{2}-4ac$. For this equation, $a=2$, $b=4$ and $c=1$
Let the discriminant be $D$. Substitute the known values into the formula and evaluate:
$D=4^{2}-4(2)(1)=16-8=8$
Since the discriminant is equal to a positive, non-perfect square number, the equation has two solutions and they are irrational numbers.