Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.4 Quadratic Equations - 1.4 Exercises - Page 122: 76

Answer

$ t=\sqrt{\frac{s-s_{0}-k}{g}},\qquad t=-\sqrt{\frac{s-s_{0}-k}{g}};,\qquad\quad g\neq 0$

Work Step by Step

Switch sides $s_{0}+g^{2}+k=s$ Subtract $s_{0}+k$ from both sides and simplify $s_{0}+g^{2}+k-\left(z_{0}+k\right)=z-\left(s_{0}+k\right)$ $gt^{2}=s-\left(s_{0}+k\right)$ Divide both sides by $g;\quad g\neq 0$ $ t^{2}=\displaystyle \frac{s-s_{0}-k}{g};,\qquad g\neq 0$ For $x^{2}=f(a)$ the solutions are $x=\sqrt{f(a)},-\sqrt{f(a)}$ $ t=\sqrt{\frac{s-s_{0}-k}{g}},\qquad t=-\sqrt{\frac{s-s_{0}-k}{g}};,\qquad\quad g\neq 0$
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