#### Answer

$ -i$

#### Work Step by Step

$i^27 = i^{24} \times i^3 = (i^4)^6 \times i^3 = 1^6 \times i^3 = 1 \times (-1)i = -i$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$ -i$

$i^27 = i^{24} \times i^3 = (i^4)^6 \times i^3 = 1^6 \times i^3 = 1 \times (-1)i = -i$

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