Answer
$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$
Work Step by Step
$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 113: 90
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