#### Answer

$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$

#### Work Step by Step

$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$

$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$

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