Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises: 90

Answer

$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$

Work Step by Step

$i^29 = i^{28} \times i = (i^4)^7 \times i = 1^7 \times i = 1 \times i = i$
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