Answer
$1$
Work Step by Step
Apply exponent rule: $\displaystyle \quad a^{-n}=\frac{1}{a^{n}}$
$\displaystyle \frac{1}{i^{-12}}=\frac{1}{(\frac{1}{i^{12}})}=i^{12}$
$ i^{12}\qquad$...Apply exponent rule: $\quad a^{bc}=(a^{b})^{c}$
$=(i^{2})^{6}\qquad$...Apply imaginary number rule: $\quad i^{2}=-1$
$=(-1)^{6}\qquad$...Apply exponent rule: $(-a)^{n}=a^{n},$ if $n$ is even.
$=1^{6}$
$=1$