## Precalculus (6th Edition)

$x=\dfrac{a^{2}+b^{2}}{b-a}$
$ax+b^{2}=bx-a^{2}$ Take $bx$ to the left side and $b^{2}$ to the right side: $ax-bx=-a^{2}-b^{2}$ Take out common factor $x$ from the left side and common factor $-1$ from the right side: $x(a-b)=-(a^{2}+b^{2})$ Take $a-b$ to divide the right side: $x=-\dfrac{a^{2}+b^{2}}{a-b}$ $x=\dfrac{a^{2}+b^{2}}{b-a}$