## Precalculus (6th Edition)

$x=\dfrac{1-2a^{2}}{1-4a}$
$\dfrac{x-1}{2a}=2x-a$ Take $2a$ to multiply the right side: $x-1=2a(2x-a)$ Take $1$ to the right side: $x=1+2a(2x-a)$ Evaluate the product on the right side: $x=1+4ax-2a^{2}$ Take $4ax$ to subtract the left side: $x-4ax=1-2a^{2}$ Take out common factor $x$ from the left side: $x(1-4a)=1-2a^{2}$ Take $1-4a$ to divide the right side: $x=\dfrac{1-2a^{2}}{1-4a}$