Precalculus (6th Edition)

$x=-24$
Multiply $12$ to both sides of the equation to obtain: $12(\frac{2}{3}x+0.25x)=12(x+2)$ Distribute $12$ to obtain: $12(\frac{2}{3}x)+12(0.25x)=12(x) + 12(2) \\8x+3x=12x+24 \\11x=12x+24$ Subtract $11x$ and $24$ to both sides: $11x-11x-24=12x+24-11x-24 \\-24=x$