Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.1 Linear Equations - 1.1 Exercises - Page 92: 9



Work Step by Step

Solve for $h$ in the equation performing the following steps: (1) Multiply $2$ to both sides: $2(A) = 2(\frac{1}{2}bh) \\2A = bh$ (2) Divide both sides of the equation by $b$ to obtain: $\dfrac{2A}{b} = \dfrac{bh}{b} \\\dfrac{2A}{b} = h$ Thus, the given statement is false.
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