## Precalculus (6th Edition)

Solve for $h$ in the equation performing the following steps: (1) Multiply $2$ to both sides: $2(A) = 2(\frac{1}{2}bh) \\2A = bh$ (2) Divide both sides of the equation by $b$ to obtain: $\dfrac{2A}{b} = \dfrac{bh}{b} \\\dfrac{2A}{b} = h$ Thus, the given statement is false.