Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.1 Linear Equations - 1.1 Exercises - Page 92: 24



Work Step by Step

Multiply 100 to both sides of the equation to obtain: $100(0.01x+3.1)=100(2.03x-2.96)$ Distribute $100$ to obtain: $100(0.01x)+100(3.1) = 100(2.03x)-100(2.96) \\x+310=203x-296$ Subtract $x$ and add $296$ to both sides of the equation, then combine like terms to obtain: $x+310-x+296=203x-296-x+296 \\606=202x$ Divide $202$ to both sides of the equation to obtain: $\dfrac{606}{202} = \dfrac{202x}{202} \\3=x$ Thus, the solution tot he given equation is $3$.
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