## Precalculus (6th Edition)

$x=-1$
Distribute $4$ to obtain: $4(-2x)+4(1)=6-(2x-4) \\-8x+4=6-(2x-4)$ Subtract each term of the binomial to obtain: $-8x+4=6-2x-(-4) \\-8x+4=6-2x+4 \\-8x+4=-2x+10$ Add $8x$ and subtract $10$ to both sides, then combine like terms to obtain: $-8x+4+8x-10=-2x+10+8x-10 \\-6=6x$ Divide $6$ to both sides: $\dfrac{-6}{6} = \dfrac{6x}{6} \\-1=x$