Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Test: 9

Answer

The required value is $2x\sqrt[3]{2x}$

Work Step by Step

Consider the expression, $\sqrt[3]{16{{x}^{4}}}$ The given expression can be further evaluated as $\begin{align} & \sqrt[3]{16{{x}^{4}}}=\sqrt[3]{\left( 8 \right)\left( 2 \right)\left( {{x}^{3}} \right)\left( x \right)} \\ & =\sqrt[3]{8}\sqrt[3]{{{x}^{3}}}\sqrt[3]{2x} \\ & =\sqrt[3]{{{\left( 2 \right)}^{2}}}\sqrt[3]{{{\left( x \right)}^{3}}}\sqrt[3]{2x} \\ & =2x\sqrt[3]{2x} \end{align}$ Therefore, the value of $\sqrt[3]{16{{x}^{4}}}$ is $2x\sqrt[3]{2x}$.
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