Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Test: 8

Answer

$\frac{15-3\sqrt 2}{23}$

Work Step by Step

$\frac{3}{5+\sqrt 2}=\frac{3(5-\sqrt 2)}{(5+\sqrt 2)(5-\sqrt 2)}=\frac{15-3\sqrt 2}{25-2}=\frac{15-3\sqrt 2}{23}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.