Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Test - Page 146: 20


The required value is $\left( {{x}^{2}}+3 \right)\left( x+2 \right)$.

Work Step by Step

Consider the expression, ${{x}^{3}}+2{{x}^{2}}+3x+6$ The given expression can be evaluated as: $\begin{align} & {{x}^{3}}+2{{x}^{2}}+3x+6={{x}^{^{2}}}\left( x+2 \right)+3\left( x+2 \right) \\ & =\left( {{x}^{2}}+3 \right)\left( x+2 \right) \end{align}$ Therefore, the value of ${{x}^{3}}+2{{x}^{2}}+3x+6$ is $\left( {{x}^{2}}+3 \right)\left( x+2 \right)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.