Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Test - Page 146: 21

Answer

The required value is $\left( 5x+3 \right)\left( 5x-3 \right)$.

Work Step by Step

Consider the expression, $25{{x}^{2}}-9$ The given expression can be evaluated as: $25{{x}^{2}}-9={{\left( 5x \right)}^{2}}-{{\left( 3 \right)}^{2}}$ Use the following formula: ${{A}^{2}}-{{B}^{2}}=\left( A+B \right)\left( A-B \right)$ Then, the expression is: $25{{x}^{2}}-9=\left( 5x+3 \right)\left( 5x-3 \right)$ Therefore, the value of $25{{x}^{2}}-9$ is $\left( 5x+3 \right)\left( 5x-3 \right)$.
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