Answer
For the quadratic equation $ ax^{2}+bx+c=0$, we can find solutions using the
Quadratic formula: $\displaystyle \quad x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
Here, $ a=1, b=6, c=8$.
Insert these value into the formula and calculate
$ x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{-6\pm\sqrt{36-4(1)(8)}}{2(1)}$
$=\displaystyle \frac{-6\pm\sqrt{4}}{2}=\frac{-6\pm 2}{2}$
$ x=-4$ or $ x=-2$
Solution set =$ \{-4,-2\}$
Work Step by Step
Given above.
