Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 107: 139

Answer

The number of liters of peroxide that should be added to produce a new product is $125$ liters.

Work Step by Step

The provided mathematical model is, $C=\frac{x+0.1\left( 500 \right)}{x+500}$. The concentration of pure peroxide is $C$, which is equal to $28percent\text{ or 0}\text{.28}$ in the new product. Substitute $0.28$ for $C$ in the equation $C=\frac{x+0.1\left( 500 \right)}{x+500}$. $\begin{align} & C=\frac{x+0.1\left( 500 \right)}{x+500} \\ & 0.28=\frac{x+0.1\left( 500 \right)}{x+500} \\ & 0.28\left( x+500 \right)=x+0.1\left( 500 \right) \\ & 0.28x+140=x+50 \end{align}$ Further simplify the above equation. $\begin{align} & 0.28x+140=x+50 \\ & -0.72x=-90 \\ & x=125 \end{align}$ Therefore, the amount of the pure peroxide added is $125$ liters.
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