Answer
Solution set:$ \; \{-2\}$.
Work Step by Step
Simplify each side of the equation
$\left.\begin{array}{lll}
\mathrm{L}\mathrm{H}\mathrm{S} = & ... & RHS=\\
= 25-[2+5y-3(y+2)] & & =-3(2y-5)-[5(y-1)-3y+3]\\
=25-[2+5y-3y-6] & & =-6y+15-[5y-5-3y+3]\\
=25-[2y-4] & & =-6y+15-[2y-2]\\
=25-2y+4 & & =-6y+15-2y+2\\
=-2y+29 & & =-8y+17\\
& &
\end{array}\right.$
The equation simplifies to
$-2y+29=-8y+17\qquad $ ... add $8y-29$
$6y=-12$
$ y=-2$
Solution set:$ \; \{-2\}$.
