Answer
$(3x+4)$
Work Step by Step
We multiply the expression with 1, but we write 1 as $\displaystyle \frac{3x+4}{3x+4}$
so, $\displaystyle \quad \frac{3x+2}{x-5}\cdot\frac{3x+4}{3x+4}=\frac{(3x+2)(3x+4)}{(x-5)(3x+4)}$
has the denominator $(x-5)(3x+4)$.
We multiplied the numerator and denominator with $(3x+4)$
