Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Concept and Vocabulary Check - Page 84: 11

Answer

Fill the blank with $\sqrt{x}$.

Work Step by Step

This is a complex fraction (has a fraction in the numerator). Our first goal is to eliminate the fraction in the numerator. If we multiply the numerator with $\sqrt{x}$, the numerator will equal $\displaystyle \sqrt{x}(\sqrt{x}+\frac{1}{\sqrt{x}})=x+1$ we must also multiply the denominator with $\sqrt{x},$ in order not to change the value of the initial expression. The whole expression, after multiplying with $\displaystyle \frac{\sqrt{x}}{\sqrt{x}}$ equals $\displaystyle \frac{x+1}{x\sqrt{x}}$ (there is more work to be done - such as rationalizing the denominator, but this expression is simpler - it is not complex any more ) Fill the blank with $\sqrt{x}$
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