## Precalculus (6th Edition) Blitzer

$\left( 4x+1 \right)\left( 2x-3 \right)=8{{x}^{2}}-10x-3$
We have to calculate the factors of the expression $8{{x}^{2}}-10x-3$: \begin{align} & 8{{x}^{2}}-10x-3=8{{x}^{2}}-12x+2x-3 \\ & =4x\left( 2x-3 \right)+1\left( 2x-3 \right) \\ & =\left( 4x+1 \right)\left( 2x-3 \right) \end{align} Thus, the solution is $\left( 4x+1 \right)\left( 2x-3 \right)=8{{x}^{2}}-10x-3$.