Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.4 - Polynomials - Exercise Set - Page 58: 113


$\left( 4x+1 \right)\left( 2x-3 \right)=8{{x}^{2}}-10x-3$

Work Step by Step

We have to calculate the factors of the expression $8{{x}^{2}}-10x-3$: $\begin{align} & 8{{x}^{2}}-10x-3=8{{x}^{2}}-12x+2x-3 \\ & =4x\left( 2x-3 \right)+1\left( 2x-3 \right) \\ & =\left( 4x+1 \right)\left( 2x-3 \right) \end{align}$ Thus, the solution is $\left( 4x+1 \right)\left( 2x-3 \right)=8{{x}^{2}}-10x-3$.
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