Answer
$\left( 4x+1 \right)\left( 2x-3 \right)=8{{x}^{2}}-10x-3$
Work Step by Step
We have to calculate the factors of the expression $8{{x}^{2}}-10x-3$:
$\begin{align}
& 8{{x}^{2}}-10x-3=8{{x}^{2}}-12x+2x-3 \\
& =4x\left( 2x-3 \right)+1\left( 2x-3 \right) \\
& =\left( 4x+1 \right)\left( 2x-3 \right)
\end{align}$
Thus, the solution is $\left( 4x+1 \right)\left( 2x-3 \right)=8{{x}^{2}}-10x-3$.
