Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.4 - Polynomials - Exercise Set - Page 58: 110

Answer

$6y^n-13$

Work Step by Step

Using formulas $(A+B)(A-B)=A^2-B^2$ and $(A-B)^2=A^2-2AB+B^2$, we have $(y^n+2)(y^n-2)-(y^n-3)^2=y^{2n}-4-(y^{2n}-6y^n+9)=6y^n-13$
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