Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.4 - Polynomials - Exercise Set - Page 56: 90

Answer

$25x^2-30x+9$

Work Step by Step

Assuming $x\ne\frac{3}{5}$, we have $\frac{(5x-3)^6}{(5x-3)^4}=(5x-3)^2=25x^2-30x+9$
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