Answer
$27x^3-108x^2+144x-64$
Work Step by Step
RECALL:
$(a-b)^3=a^3-3a^2b+ 3ab^2-b^3$
Use the formula above with $a=3x$ and $b=4$ to obtain:
$=(3x)^3-3(3x)^2(4)+3(3x)(4^2)-4^3
\\=27x^3-12(9x^2)+9x(16)-64
\\=27x^3-108x^2+144x-64$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.4 - Polynomials - Exercise Set - Page 56: 57
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