Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.4 - Polynomials - Exercise Set: 57

Answer

$27x^3-108x^2+144x-64$

Work Step by Step

RECALL: $(a-b)^3=a^3-3a^2b+ 3ab^2-b^3$ Use the formula above with $a=3x$ and $b=4$ to obtain: $=(3x)^3-3(3x)^2(4)+3(3x)(4^2)-4^3 \\=27x^3-12(9x^2)+9x(16)-64 \\=27x^3-108x^2+144x-64$
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