Work Step by Step
RECALL: $(a-b)^3=a^3-3a^2b+ 3ab^2-b^3$ Use the formula above with $a=3x$ and $b=4$ to obtain: $=(3x)^3-3(3x)^2(4)+3(3x)(4^2)-4^3 \\=27x^3-12(9x^2)+9x(16)-64 \\=27x^3-108x^2+144x-64$
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