Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 47: 122

Answer

See explanations.

Work Step by Step

Step 1. Simplify $\sqrt {12}=\sqrt {2\times2\times3}=2\sqrt 3$ Step 2. Take the sum $\sqrt 3+\sqrt {12}=\sqrt 3+2\sqrt 3=3\sqrt 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.