Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 47: 121

Answer

See explanations.

Work Step by Step

Step 1. Using the formula $\sqrt a\sqrt b=\sqrt {ab}$, we have $\sqrt {10}\sqrt 5=\sqrt {10\cdot 5}$ Step 2. Factor to get $\sqrt {10\cdot 5}=\sqrt {2\cdot5\cdot 5}$ Step 3. Using the formula $\sqrt {a\cdot a}=\sqrt {a^2}=|a|$, we have $\sqrt {2\cdot5\cdot 5}=\sqrt 2\sqrt {5\cdot 5}=5\sqrt 2$
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