Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Test - Page 1037: 1

Answer

See graph and explanations.
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Work Step by Step

Step 1. Graph the conic section as shown in the figure. Step 2. Rewrite the equation as $\frac{x^2}{4}-\frac{y^2}{9}=1$. We can identify it is a hyperbolas with $a=2,b=3,c=\sqrt {13}$. Step 3. We can find the foci at $(\pm\sqrt {13},0)$ and the equations of the asymptotes as $y=\pm\frac{3}{2}x$
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