Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Test - Page 1037: 15

Answer

$\frac{(x-1)^2}{9}+\frac{y^2}{4}=1$ See graph.

Work Step by Step

Step 1. Using the given equations, we have $sin(t)=\frac{x-1}{3}$ and $cos(t)=\frac{y}{2}$ Step 2. Using the identify $sin^2t+cos^2t=1$, we have $(\frac{x-1}{3})^2+(\frac{y}{2})^2=1$ or $\frac{(x-1)^2}{9}+\frac{y^2}{4}=1$ Step 3. We can graph the ellipse as shown in the figure.
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