#### Answer

See graph and explanations.

#### Work Step by Step

Step 1. Given $\theta=35^\circ, v_0=300\ ft/s, h=0$, we can write the position of the projectile as
$x=(300cos35^\circ) t, y=(300sin35^\circ) t-16t^2$
where $t$ is the time.
Step 2. We can graph the parametric equations as shown in the figure.
Step 3. We can identify the maximum height as $y_m\approx462.6\ ft$ at time $t\approx5.4\ sec$
Step 4. We can also identify the range of the projectile as $x_m\approx2643.0\ ft$ at time $t\approx10.8\ sec$ when the projectile hits the ground.