#### Answer

See graph and explanations.

#### Work Step by Step

Step 1. Given $\theta=55^\circ, v_0=200\ ft/s, h=0$, we can write the position of the projectile as
$x=(200cos55^\circ) t, y=(200sin55^\circ) t-16t^2$
where $t$ is the time.
Step 2. We can graph the parametric equations as shown in the figure.
Step 3. We can identify the maximum height as $y_m\approx419.4\ ft$ at the time $t\approx5.1\ sec$
Step 4. We can also identify the range of the projectile as $x_m\approx1174.6\ ft$ at the time $t\approx10.2\ sec$ when the projectile hits the ground.