## Precalculus (6th Edition) Blitzer

Step 1. Given equation $y^2=4(x+1)$, we have $4p=4, p=1$ with the parabola opening to the right and a vertex $(-1,0)$ Step 2. We can identify its focus at $(0,0)$ and directrix as $x=-2$ Step 3. We can graph the equation as shown in the figure.