Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.4 - Rotation of Axes - Exercise Set - Page 1011: 63


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Work Step by Step

Starting from the left hand side, we have $ LHS= \frac{1/cos(x)}{cos(x)/sin(x)+sin(x)/cos(x)}= \frac{1/cos(x)}{cos(x)/sin(x)+sin(x)/cos(x)}\times\frac{sin(x)cos(x)}{sin(x)cos(x)}=\frac{sin(x)}{cos^2x+sin^2x}=sin(x)=RHS$ Thus, we have verified the identity.
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