Answer
0
Work Step by Step
Comparing the given equation with the standard form, we have
$A=3, B=-2\sqrt 3, C=1$
Thus
$B^2-4AC=(-2\sqrt 3)^2-4(3)(1)=12-12=0$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 999: 107
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