Work Step by Step
Comparing the given equation with the standard form, we have $A=3, B=-2\sqrt 3, C=1$ Thus $B^2-4AC=(-2\sqrt 3)^2-4(3)(1)=12-12=0$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.