Answer
$(-2,3)$
Work Step by Step
Step 1. From the given system, we have
$D=\begin{vmatrix} 1 & -1 \\ 3 & 2 \end{vmatrix}=2+3=5$
Step 2. From the given system, we have
$D_x=\begin{vmatrix} -5 & -1 \\ 0 & 2 \end{vmatrix}=-10+0=-10$
Step 3. From the given system, we have
$D_y=\begin{vmatrix} 1 & -5 \\ 3 & 0 \end{vmatrix}=0+15=15$
Step 4. Using the Cramer’s Rule, we have $x=\frac{D_x}{D}=-2$ and $y=\frac{D_y}{D}=3$. Thus the solution to the system is $(-2,3)$
