## Precalculus (6th Edition) Blitzer

As per the given statement , we have Depth: $y=2$ and Diameter = 6 feet. This implies that Radius: $2x=6 \implies x=3$ Now, consider $x^2=4py$ This implies that $(3)^2=(4p)(2) \implies p=1.125$ Hence, the receiver must be placed at 1.125 feet from the base of the smaller dish.