Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 998: 71

Answer

The receiver must be placed at 4.5 feet from the base of the dish.

Work Step by Step

As per the given statement , we have Depth: $y=2$ and Diameter = 12 feet. This implies that Radius: $2x=12 \implies x=6$ Now, consider $x^2=4py$ This implies that $(6)^2=(4p)(2) \implies p=4.5$ Hence, the receiver must be placed at 4.5 feet from the base of the dish.
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