## Precalculus (6th Edition) Blitzer

Asymptotoes : $y =\pm \dfrac{5}{3} x$ Foci: $(\sqrt {34},0)$, $(-\sqrt {34},0)$
The given equation is in the form of $\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$ This implies that $a^2 =9$ and $b^2=25$ and the vertices are: $(-3,0), (3,0)$ The, we have the asymptotes: $y =\pm \dfrac{b}{a} x \implies y =\pm \dfrac{5}{3} x$ $c^2=a^2+b^2 \implies c =\sqrt {34} \approx 5.83$ Hence, our result is: Asymptotoes : $y =\pm \dfrac{5}{3} x$ Foci: $(\sqrt {34},0)$, $(-\sqrt {34},0)$