Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 981: 13


Asymptotoes : $ y =\pm \dfrac{5}{3} x $ Foci: $(\sqrt {34},0)$, $(-\sqrt {34},0)$

Work Step by Step

The given equation is in the form of $\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$ This implies that $a^2 =9$ and $b^2=25$ and the vertices are: $(-3,0), (3,0)$ The, we have the asymptotes: $ y =\pm \dfrac{b}{a} x \implies y =\pm \dfrac{5}{3} x $ $ c^2=a^2+b^2 \implies c =\sqrt {34} \approx 5.83$ Hence, our result is: Asymptotoes : $ y =\pm \dfrac{5}{3} x $ Foci: $(\sqrt {34},0)$, $(-\sqrt {34},0)$
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