Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 981: 19

Answer

asymptotes: $y= \pm\frac{1}{2}x$ foci: $(0, \pm\frac{\sqrt {5}}{2})$

Work Step by Step

Step 1. From the given equation $\frac{y^2}{1/4}-\frac{x^2}{1}=1$, we have $a=\frac{1}{2}, b=1, c=\sqrt {a^2+b^2}=\frac{\sqrt {5}}{2}$ centered at $(0,0)$ with a vertical transverse axis. Step 2. We can find the vertices as $(0,\pm\frac{1}{2})$ and asymptotes as $y=\frac{a}{b}x=\pm\frac{1}{2}x$ Step 3. We can graph the equation as shown in the figure with foci at $(0, \pm\frac{\sqrt {5}}{2})$
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