## Precalculus (6th Edition) Blitzer

See figure. $(1,0)$ and $(0,-2)$
Step 1. Graph the given equations $\begin{cases} 4x^2+y^2=4 \\ 2x-y=2 \end{cases}$ as shown in the figure. Step 2. We can identify the intersection points as $(1,0)$ and $(0,-2)$ Step 3. Checking the solutions with the first equation, we have $4(1)^2+(0)^2=4$ and $4(0)^2+(-2)^2=4$ Step 4. Checking the solutions with the second equation, we have $2(1)-(0)=2$ and $2(0)-(-2)=2$