## Precalculus (6th Edition) Blitzer

$(0,3)$ See figure below:
Step 1. Graph the given equations $\begin{cases} \frac{x^2}{25}+\frac{y^2}{9}=1 \\ y=3 \end{cases}$ as shown in the figure. Step 2. We can identify the intersect points as $(0,3)$ Step 3. Checking the solution with the first equation, we have $\frac{0^2}{25}+\frac{3^2}{9}=1$ Step 4. Checking the solution with the second equation, we have $3=3$