Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.5 - Determinants and Cramer's Rule - Exercise Set - Page 945: 15



Work Step by Step

As per Cramer's Rule , we have $x=\dfrac{D_x}{D}$ and $y=\dfrac{D_y}{D}$ The general formula to calculate the determinant of a $2 \times 2$ matrix which has 2 rows and 2 columns, such as: $D=\begin{vmatrix}a&b\\c&d\end{vmatrix}=ad-bc$ Thus, $D=\begin{vmatrix}4&-5\\2&3\end{vmatrix}=22$ and $D_x=\begin{vmatrix}17&-5\\3&3\end{vmatrix}=66$ Also, $D_y=\begin{vmatrix}4&17\\2&3\end{vmatrix}=-22$ Now, $x=\dfrac{D_x}{D}=3$ and $y=\dfrac{D_y}{D}=-1$ Hence, $(x,y)=(3,-1)$
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