Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.1 - Matrix Solutions to Linear Systems - Exercise Set - Page 893: 15

Answer

The new matrix is, $\left[ \begin{matrix} 1 & -3 & 2 & 0 \\ 0 & 10 & -7 & 7 \\ 2 & -2 & 1 & 3 \\ \end{matrix} \right]$

Work Step by Step

Consider the provided matrix, $\left[ \begin{matrix} 1 & -3 & 2 & 0 \\ 3 & 1 & -1 & 7 \\ 2 & -2 & 1 & 3 \\ \end{matrix} \right]$ The operation $-3{{R}_{1}}+{{R}_{2}}$ implies that each element of the first row will be multiplied by $-3$ and then added with the corresponding element of the row second. The new matrix is obtained after performing the row operation ${{R}_{2}}\to -3{{R}_{1}}+{{R}_{2}}$ , $\left[ \begin{matrix} 1 & -3 & 2 & 0 \\ -3+3 & 9+1 & -6-1 & 0+7 \\ 2 & -2 & 1 & 3 \\ \end{matrix} \right]=\left[ \begin{matrix} 1 & -3 & 2 & 0 \\ 0 & 10 & -7 & 7 \\ 2 & -2 & 1 & 3 \\ \end{matrix} \right]$ Therefore, the new matrix is, $\left[ \begin{matrix} 1 & -3 & 2 & 0 \\ 0 & 10 & -7 & 7 \\ 2 & -2 & 1 & 3 \\ \end{matrix} \right]$
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